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# A Car Traveling At A Speed Of 13 M/s - Question Solved

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If you want to know the answer to the question of a car traveling at a speed of 13 m/s,you are on the right page. Here is the detailed answer. Keep reading.

Question:A car traveling at a speed of 13 m/s accelerates uniformly to a speed of 25 meters per second in 5.0 seconds.

(a) Calculate the magnitude of the acceleration of the car during this 5.0-second interval.

(b) A truck traveling at a constant speed covers the same total distance as the car in the same 5.0-second interval. Determine the speed of the truck. Answer: Acceleration of the car: 2.4 m/s^2

Explanation:

The acceleration of the car is given by:

a = v - u/t

where

v = 25 m/s is the final velocity of the car

u = 13 m/s is the initial velocity

t = 5.0 s is the time taken

Substituting the numbers into the equation, we find

a=(25m/s-13m/s)/5.0

= 2.4m/s^2

2) Speed of the truck: 19 m/s

First of all, we need to find the total distance covered by the car, which is given by the equation:

d = ut+1/2at^2

= 13m/s*5.0s+1/2(2.4m/s^2)(5.0s)^2

= 95m

The truck covers the same distance in t=5.0 s, traveling at constant speed; therefore, its speed is given by:

v=d/t

=95m/5.0s

=19m/s

Question: A car is traveling at a speed of 30 m/s encounters an emergency and comes to a complete stop. How much time will it take for a car to stop if it decelerate at-4.0 m/s2?

Answer: V = Vo + at

0 m/s = 30 m/s + (-4.0 m/s2) (t)

-30 m/s = (-4.0 m/s2) (t)

(-30 m/s) / (-4.0 m/s2) = t

t = 7.5 s

The (-) sign is for magnitude, speeding up or slowing down.

So, let's discuss the terms discussed in the above question.

So, what is acceleration?

## .nzoqai-y51p0m{color:inherit;font-size:inherit;-webkit-text-decoration:none;text-decoration:none;text-decoration-thickness:1px;}.nzoqai-y51p0m:hover{-webkit-text-decoration:underline;text-decoration:underline;}.nzoqai-y51p0m:hover::after{content:" #";opacity:0.6;-webkit-text-decoration:none;text-decoration:none;}Acceleration

Any process in which there is a change in velocity is known as acceleration. Acceleration is the word we give to this change.

Because velocity is both a speed and a direction, you can only accelerate in one of two ways: change your speed, change your direction, or change both.

### Formulas Of Acceleration

• a = (v_f - v_i) / Δt.
• a = 2 * (Δd - v_i * Δt) / Δt².
• a = F / m.

## Equation Of Motion

The one used above is the 2nd equation of motion.

The second equation of motion describes the link that exists between an object's starting velocity, its displacement, and its acceleration. t = time. 3.)

The second equation is particularly useful in obtaining the displacement, acceleration, beginning velocity, and time.

### How Do U Calculate Acceleration?

Acceleration, denoted by the letter a, is defined as the ratio of the rate of change in velocity to the rate of change in time, as seen in the equation a = v/t. Because of this, you will be able to determine the rate of change in velocity in meters per second squared (m/s2).

### What Is The Second Equation Of Motion?

This is the second equation of motion: d = ut+1/2at^2.

### What Are The 3 Equations Of Motion?

• First Equation of Motion : v = u + a t.
• Second Equation of Motion : s = u t + 1 2 a t 2.
• Third Equation of Motion : v 2 = u 2 + 2 a s.

## Conclusion

Hope you find the solution to the question of a car traveling at a speed of 13 m/s accelerating uniformly to a speed of 25 meters per second in 5.0 seconds useful. Keep visiting to learn more. 